What I mean is each light wave emerging from the slit was 1.1 wavelengths shifted compared to the previous ( just as in the constructive point you had each light wave being 1 wavelength shifted compared to the other) * and therefore, over a large number of light waves from the many slits, we had each wave cancelling out with the other*. Considering it s slightly more, as in the example David gave in the video, just as in double slit the light coming from one slit was slightly less constructive ( in the example we just set it to be skewed by 1.1 wavelengths), the light in this case coming from every slit was a little lesser constructive compared to the previous. Here's how: We know from double slit that as you move away from the constructive point the path length difference or ∆x is not exactly 1λ but is slightly more or slightly less. Multiplying D by the slit width gives an indication of the wavelength resolution.Oh so you're getting stuck on how exactly as we move away from the constructive point do waves get destructive. Here, D is called the "reciprocal linear dispersion" and represents the difference in wavelength per unit length on the surface of the exit slit in the optical system.
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